pg_field_table

    (PHP 5 >= 5.2.0, PHP 7, PHP 8)

    pg_field_table — Returns the name or oid of the tables field

    说明

    pg_field_table(PgSql\Result$result, int$field, bool$oid_only = false): string|int|false

    pg_field_table() returns the name of the table that field belongs to, or the table's oid if oid_only is true.

    参数

    result

    PgSql\Result 实例，由 pg_query()、pg_query_params() 或者 pg_execute()（等）返回。

    field

    Field number, starting from 0.

    oid_only

    By default the tables name that field belongs to is returned but if oid_only is set to true, then the oid will instead be returned.

    返回值

    On success either the fields table name or oid, 或者在失败时返回 false.

    更新日志

    版本说明
    8.1.0 现在 result 参数接受 PgSql\Result 实例，之前接受 resource。

    示例

    示例 #1 Getting table information about a field

    <?php
    $dbconn     = pg_connect("dbname=publisher") or die("Could not connect");

    $res = pg_query($dbconn, "SELECT bar FROM foo");

    echo     pg_field_table($res, 0);
    echo     pg_field_table($res, 0, true);

    $res = pg_query($dbconn, "SELECT version()");
    var_dump(pg_field_table($res, 0));
    ?>

    以上示例的输出类似于：

    foo 14379580 bool(false)

    注释

    注意:

    Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.

    参见

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