(PHP 5, PHP 7, PHP 8)
mysqli_stmt::$param_count -- mysqli_stmt_param_count — Returns the number of parameters for the given statement
面向对象风格
过程化风格
Returns the number of parameter markers present in the prepared statement.
statement
仅以过程化样式:由 mysqli_stmt_init() 返回的 mysqli_stmt 对象。
Returns an integer representing the number of parameters.
示例 #1 面向对象风格
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if ($stmt = $mysqli->prepare("SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = $stmt->param_count;
printf("Statement has %d markers.\n", $marker);
$stmt->close();
}
$mysqli->close();
?>
示例 #2 过程化风格
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if ($stmt = mysqli_prepare($link, "SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = mysqli_stmt_param_count($stmt);
printf("Statement has %d markers.\n", $marker);
mysqli_stmt_close($stmt);
}
mysqli_close($link);
?>
以上示例会输出:
Statement has 2 markers.